What is a distribution feature?
The
distribution property is expressed in mathematics as the following equation: A (B + C) = AB + AC. You can read it because the sum A (B + C) is equal to the sum of times B A and Times C. When you look at such an equation, you can see that the multiplication part evenly distributes to all numbers in parentheses. It would be wrong to multiply AB and just add C or multiply AC and add b. The distribution feature reminds us that everything in parentheses must be multiplied by an external number. This is the concept that in problems where there are various mathematical operations such as multiple, census, subtraction, parentheses, you must work in a certain order to get the right answer. This order is parentheses, exponents, multiplication and division. and census and subtraction that can be shortened to Pemdas.
When you are a mathematical problem that uses the brackets you need to solve what is first in brackets before you can move to solve other problems. If he has a mathematical problem JIt is quite easy to solve. 2 (10 + 5) becomes 2 (15) or equals under the distribution feature 2 (10) + 2 (5). What is complicated is when you work with variables (A, B, X, Y, etc.) in algebers, and when these variables cannot be combined together.
consider equation 9 (10a + 2). If we do not know what the and variable means, we cannot add 10A + 2, but using the distribution properties, this expression still allows us to simply this expression, because we know that this equation is equal to 9 (10A) + 9 (2). In order to simply introduce the expression each part separately and multiply it to 9 and get 90A + 18.
Another way to use the distribution feature is if you want to feature similarities in the equation. In example 90A + 18, although the conditions are not like, they have something in common. You can work backwards and remove factor 9 and unlike parentheses. 90a + 18can equal 9 (A +2). We have removed an element that is common for these terms, a common factor 9.
Why would you like to work on the country with the distribution feature back? Let's say you have an equation that 4A + 4 = 8. Use of distribution properties before we get to deduct the conditions to solve A, can simplify the work. You can divide the whole equation on both sides 4, which gives us an answer A + 1 = 2. From there it is easy to determine that A = 1 sometimes makes sense to reduce the equation more easily by their common factor.